Sr Examen

Expresión xy~z->y

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (x∧y)⇔(z⇒y)
    $$\left(x \wedge y\right) ⇔ \left(z \Rightarrow y\right)$$
    Solución detallada
    $$z \Rightarrow y = y \vee \neg z$$
    $$\left(x \wedge y\right) ⇔ \left(z \Rightarrow y\right) = \left(x \wedge y\right) \vee \left(z \wedge \neg y\right)$$
    Simplificación [src]
    $$\left(x \wedge y\right) \vee \left(z \wedge \neg y\right)$$
    (x∧y)∨(z∧(¬y))
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    $$\left(x \wedge y\right) \vee \left(z \wedge \neg y\right)$$
    (x∧y)∨(z∧(¬y))
    FND [src]
    Ya está reducido a FND
    $$\left(x \wedge y\right) \vee \left(z \wedge \neg y\right)$$
    (x∧y)∨(z∧(¬y))
    FNCD [src]
    $$\left(x \vee \neg y\right) \wedge \left(y \vee z\right)$$
    (y∨z)∧(x∨(¬y))
    FNC [src]
    $$\left(x \vee z\right) \wedge \left(x \vee \neg y\right) \wedge \left(y \vee z\right) \wedge \left(y \vee \neg y\right)$$
    (x∨z)∧(y∨z)∧(x∨(¬y))∧(y∨(¬y))