Expresión xy~z->y
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$z \Rightarrow y = y \vee \neg z$$
$$\left(x \wedge y\right) ⇔ \left(z \Rightarrow y\right) = \left(x \wedge y\right) \vee \left(z \wedge \neg y\right)$$
$$\left(x \wedge y\right) \vee \left(z \wedge \neg y\right)$$
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(x \wedge y\right) \vee \left(z \wedge \neg y\right)$$
Ya está reducido a FND
$$\left(x \wedge y\right) \vee \left(z \wedge \neg y\right)$$
$$\left(x \vee \neg y\right) \wedge \left(y \vee z\right)$$
$$\left(x \vee z\right) \wedge \left(x \vee \neg y\right) \wedge \left(y \vee z\right) \wedge \left(y \vee \neg y\right)$$
(x∨z)∧(y∨z)∧(x∨(¬y))∧(y∨(¬y))