Sr Examen

Expresión yx⇒(z+yx)=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ¬((x∧y)⇒(z∨(x∧y)))
    $$\left(x \wedge y\right) \not\Rightarrow \left(z \vee \left(x \wedge y\right)\right)$$
    Solución detallada
    $$\left(x \wedge y\right) \Rightarrow \left(z \vee \left(x \wedge y\right)\right) = 1$$
    $$\left(x \wedge y\right) \not\Rightarrow \left(z \vee \left(x \wedge y\right)\right) = \text{False}$$
    Simplificación [src]
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    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
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    0
    FNDP [src]
    0
    0
    FND [src]
    Ya está reducido a FND
    0
    0
    FNCD [src]
    0
    0