Sr Examen
Expresión yx⇒(z+yx)=0
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Solución
Ha introducido
[src]
¬((x∧y)⇒(z∨(x∧y)))
$$\left(x \wedge y\right) \not\Rightarrow \left(z \vee \left(x \wedge y\right)\right)$$
Solución detallada
$$\left(x \wedge y\right) \Rightarrow \left(z \vee \left(x \wedge y\right)\right) = 1$$
$$\left(x \wedge y\right) \not\Rightarrow \left(z \vee \left(x \wedge y\right)\right) = \text{False}$$
$$\left(x \wedge y\right) \not\Rightarrow \left(z \vee \left(x \wedge y\right)\right) = \text{False}$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+