Sr Examen
Lógica matemática/ ¬x¬z¬t+¬xyt+yz¬t+x¬y+xy¬z+xyzt

Expresión ¬x¬z¬t+¬xyt+yz¬t+x¬y+xy¬z+xyzt

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (x∧(¬y))∨(t∧y∧(¬x))∨(x∧y∧(¬z))∨(y∧z∧(¬t))∨(t∧x∧y∧z)∨((¬t)∧(¬x)∧(¬z))
    $$\left(x \wedge \neg y\right) \vee \left(t \wedge y \wedge \neg x\right) \vee \left(x \wedge y \wedge \neg z\right) \vee \left(y \wedge z \wedge \neg t\right) \vee \left(\neg t \wedge \neg x \wedge \neg z\right) \vee \left(t \wedge x \wedge y \wedge z\right)$$
    Solución detallada
    $$\left(x \wedge \neg y\right) \vee \left(t \wedge y \wedge \neg x\right) \vee \left(x \wedge y \wedge \neg z\right) \vee \left(y \wedge z \wedge \neg t\right) \vee \left(\neg t \wedge \neg x \wedge \neg z\right) \vee \left(t \wedge x \wedge y \wedge z\right) = x \vee y \vee \left(\neg t \wedge \neg z\right)$$
    Simplificación [src]
    $$x \vee y \vee \left(\neg t \wedge \neg z\right)$$ 
    x∨y∨((¬t)∧(¬z))
    Tabla de verdad 
    +---+---+---+---+--------+
| t | x | y | z | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FNCD [src]
    $$\left(x \vee y \vee \neg t\right) \wedge \left(x \vee y \vee \neg z\right)$$ 
    (x∨y∨(¬t))∧(x∨y∨(¬z))
    FNDP [src]
    $$x \vee y \vee \left(\neg t \wedge \neg z\right)$$ 
    x∨y∨((¬t)∧(¬z))
    FND [src]
    Ya está reducido a FND
    $$x \vee y \vee \left(\neg t \wedge \neg z\right)$$ 
    x∨y∨((¬t)∧(¬z))
    FNC [src]
    $$\left(x \vee y \vee \neg t\right) \wedge \left(x \vee y \vee \neg z\right)$$ 
    (x∨y∨(¬t))∧(x∨y∨(¬z))
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