Sr Examen
Expresión xy'+x'z
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(z∧(¬x))∨(¬(x∧y))
$$\left(z \wedge \neg x\right) \vee \neg \left(x \wedge y\right)$$
Solución detallada
$$\neg \left(x \wedge y\right) = \neg x \vee \neg y$$
$$\left(z \wedge \neg x\right) \vee \neg \left(x \wedge y\right) = \neg x \vee \neg y$$
$$\left(z \wedge \neg x\right) \vee \neg \left(x \wedge y\right) = \neg x \vee \neg y$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+