Sr Examen

Expresión (x&(x&y)&(xvy))v((x&yvx)⊕(x⊕(xvy)))

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (x∧y∧(x∨y))∨(x⊕(x∨y)⊕(x∨(x∧y)))
    (xy(xy))(x(xy)(x(xy)))\left(x \wedge y \wedge \left(x \vee y\right)\right) \vee \left(x ⊕ \left(x \vee y\right) ⊕ \left(x \vee \left(x \wedge y\right)\right)\right)
    Solución detallada
    xy(xy)=xyx \wedge y \wedge \left(x \vee y\right) = x \wedge y
    x(xy)=xx \vee \left(x \wedge y\right) = x
    x(xy)(x(xy))=xyx ⊕ \left(x \vee y\right) ⊕ \left(x \vee \left(x \wedge y\right)\right) = x \vee y
    (xy(xy))(x(xy)(x(xy)))=xy\left(x \wedge y \wedge \left(x \vee y\right)\right) \vee \left(x ⊕ \left(x \vee y\right) ⊕ \left(x \vee \left(x \wedge y\right)\right)\right) = x \vee y
    Simplificación [src]
    xyx \vee y
    x∨y
    Tabla de verdad
    +---+---+--------+
    | x | y | result |
    +===+===+========+
    | 0 | 0 | 0      |
    +---+---+--------+
    | 0 | 1 | 1      |
    +---+---+--------+
    | 1 | 0 | 1      |
    +---+---+--------+
    | 1 | 1 | 1      |
    +---+---+--------+
    FNCD [src]
    xyx \vee y
    x∨y
    FND [src]
    Ya está reducido a FND
    xyx \vee y
    x∨y
    FNDP [src]
    xyx \vee y
    x∨y
    FNC [src]
    Ya está reducido a FNC
    xyx \vee y
    x∨y