Expresión AvA&(CvB)&(AvB)vB&C
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
a∧(a∨b)∧(b∨c)=a∧(b∨c)a∨(b∧c)∨(a∧(a∨b)∧(b∨c))=a∨(b∧c)
a∨(b∧c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FND
a∨(b∧c)
(a∨b)∧(a∨c)
(a∨b)∧(a∨c)
a∨(b∧c)