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Expresión (((¬A∨B)⇒C)∨(¬D⇒((B∧C)∨A)))

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    Solución

    Ha introducido [src]
    ((b∨(¬a))⇒c)∨((¬d)⇒(a∨(b∧c)))
    (¬d(a(bc)))((b¬a)c)\left(\neg d \Rightarrow \left(a \vee \left(b \wedge c\right)\right)\right) \vee \left(\left(b \vee \neg a\right) \Rightarrow c\right)
    Solución detallada
    (b¬a)c=c(a¬b)\left(b \vee \neg a\right) \Rightarrow c = c \vee \left(a \wedge \neg b\right)
    ¬d(a(bc))=ad(bc)\neg d \Rightarrow \left(a \vee \left(b \wedge c\right)\right) = a \vee d \vee \left(b \wedge c\right)
    (¬d(a(bc)))((b¬a)c)=acd\left(\neg d \Rightarrow \left(a \vee \left(b \wedge c\right)\right)\right) \vee \left(\left(b \vee \neg a\right) \Rightarrow c\right) = a \vee c \vee d
    Simplificación [src]
    acda \vee c \vee d
    a∨c∨d
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNCD [src]
    acda \vee c \vee d
    a∨c∨d
    FND [src]
    Ya está reducido a FND
    acda \vee c \vee d
    a∨c∨d
    FNC [src]
    Ya está reducido a FNC
    acda \vee c \vee d
    a∨c∨d
    FNDP [src]
    acda \vee c \vee d
    a∨c∨d