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Lógica matemática/ abc∨a|bc

Expresión abc∨a|bc

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    Solución

    Ha introducido [src] 
    (a∨(a∧b∧c))|(b∧c)
    (a∨(a∧b∧c))∣(b∧c)\left(a \vee \left(a \wedge b \wedge c\right)\right) | \left(b \wedge c\right)
    Solución detallada
    a∨(a∧b∧c)=aa \vee \left(a \wedge b \wedge c\right) = a
    (a∨(a∧b∧c))∣(b∧c)=¬a∨¬b∨¬c\left(a \vee \left(a \wedge b \wedge c\right)\right) | \left(b \wedge c\right) = \neg a \vee \neg b \vee \neg c
    Simplificación [src]
    ¬a∨¬b∨¬c\neg a \vee \neg b \vee \neg c 
    (¬a)∨(¬b)∨(¬c)
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 0      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    ¬a∨¬b∨¬c\neg a \vee \neg b \vee \neg c 
    (¬a)∨(¬b)∨(¬c)
    FNCD [src]
    ¬a∨¬b∨¬c\neg a \vee \neg b \vee \neg c 
    (¬a)∨(¬b)∨(¬c)
    FNDP [src]
    ¬a∨¬b∨¬c\neg a \vee \neg b \vee \neg c 
    (¬a)∨(¬b)∨(¬c)
    FNC [src]
    Ya está reducido a FNC
    ¬a∨¬b∨¬c\neg a \vee \neg b \vee \neg c 
    (¬a)∨(¬b)∨(¬c)
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