Sr Examen

Expresión (¬av¬b)∧(b∧(avc)va∧c)∧(av(b∧¬c)v(c∧¬b))

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ((¬a)∨(¬b))∧((a∧c)∨(b∧(a∨c)))∧(a∨(b∧(¬c))∨(c∧(¬b)))
    $$\left(\left(a \wedge c\right) \vee \left(b \wedge \left(a \vee c\right)\right)\right) \wedge \left(\neg a \vee \neg b\right) \wedge \left(a \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)\right)$$
    Solución detallada
    $$\left(a \wedge c\right) \vee \left(b \wedge \left(a \vee c\right)\right) = \left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(b \wedge c\right)$$
    $$\left(\left(a \wedge c\right) \vee \left(b \wedge \left(a \vee c\right)\right)\right) \wedge \left(\neg a \vee \neg b\right) \wedge \left(a \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)\right) = a \wedge c \wedge \neg b$$
    Simplificación [src]
    $$a \wedge c \wedge \neg b$$
    a∧c∧(¬b)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$a \wedge c \wedge \neg b$$
    a∧c∧(¬b)
    FNCD [src]
    $$a \wedge c \wedge \neg b$$
    a∧c∧(¬b)
    FNDP [src]
    $$a \wedge c \wedge \neg b$$
    a∧c∧(¬b)
    FND [src]
    Ya está reducido a FND
    $$a \wedge c \wedge \neg b$$
    a∧c∧(¬b)