Sr Examen

Expresión ((bvc)&a)v((bvc)&c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧(b∨c))∨(c∧(b∨c))
    $$\left(a \wedge \left(b \vee c\right)\right) \vee \left(c \wedge \left(b \vee c\right)\right)$$
    Solución detallada
    $$c \wedge \left(b \vee c\right) = c$$
    $$\left(a \wedge \left(b \vee c\right)\right) \vee \left(c \wedge \left(b \vee c\right)\right) = c \vee \left(a \wedge b\right)$$
    Simplificación [src]
    $$c \vee \left(a \wedge b\right)$$
    c∨(a∧b)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    $$c \vee \left(a \wedge b\right)$$
    c∨(a∧b)
    FNC [src]
    $$\left(a \vee c\right) \wedge \left(b \vee c\right)$$
    (a∨c)∧(b∨c)
    FND [src]
    Ya está reducido a FND
    $$c \vee \left(a \wedge b\right)$$
    c∨(a∧b)
    FNCD [src]
    $$\left(a \vee c\right) \wedge \left(b \vee c\right)$$
    (a∨c)∧(b∨c)