Expresión ((bvc)&a)v((bvc)&c)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
c∧(b∨c)=c(a∧(b∨c))∨(c∧(b∨c))=c∨(a∧b)
c∨(a∧b)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
c∨(a∧b)
(a∨c)∧(b∨c)
Ya está reducido a FND
c∨(a∧b)
(a∨c)∧(b∨c)