Sr Examen

Expresión ((bvc)&a)v((bvc)&c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧(b∨c))∨(c∧(b∨c))
    (a(bc))(c(bc))\left(a \wedge \left(b \vee c\right)\right) \vee \left(c \wedge \left(b \vee c\right)\right)
    Solución detallada
    c(bc)=cc \wedge \left(b \vee c\right) = c
    (a(bc))(c(bc))=c(ab)\left(a \wedge \left(b \vee c\right)\right) \vee \left(c \wedge \left(b \vee c\right)\right) = c \vee \left(a \wedge b\right)
    Simplificación [src]
    c(ab)c \vee \left(a \wedge b\right)
    c∨(a∧b)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    c(ab)c \vee \left(a \wedge b\right)
    c∨(a∧b)
    FNC [src]
    (ac)(bc)\left(a \vee c\right) \wedge \left(b \vee c\right)
    (a∨c)∧(b∨c)
    FND [src]
    Ya está reducido a FND
    c(ab)c \vee \left(a \wedge b\right)
    c∨(a∧b)
    FNCD [src]
    (ac)(bc)\left(a \vee c\right) \wedge \left(b \vee c\right)
    (a∨c)∧(b∨c)