Sr Examen
Expresión (not(a)¬(b)&b)v(a¬(b)&b)v(a¬(b)¬(b))v(a¬(b)¬(b))
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(a∧(¬b))∨(a∧b∧(¬b))∨(b∧(¬a)∧(¬b))
$$\left(a \wedge \neg b\right) \vee \left(a \wedge b \wedge \neg b\right) \vee \left(b \wedge \neg a \wedge \neg b\right)$$
Solución detallada
$$a \wedge b \wedge \neg b = \text{False}$$
$$b \wedge \neg a \wedge \neg b = \text{False}$$
$$\left(a \wedge \neg b\right) \vee \left(a \wedge b \wedge \neg b\right) \vee \left(b \wedge \neg a \wedge \neg b\right) = a \wedge \neg b$$
$$b \wedge \neg a \wedge \neg b = \text{False}$$
$$\left(a \wedge \neg b\right) \vee \left(a \wedge b \wedge \neg b\right) \vee \left(b \wedge \neg a \wedge \neg b\right) = a \wedge \neg b$$
Tabla de verdad
+---+---+--------+ | a | b | result | +===+===+========+ | 0 | 0 | 0 | +---+---+--------+ | 0 | 1 | 0 | +---+---+--------+ | 1 | 0 | 1 | +---+---+--------+ | 1 | 1 | 0 | +---+---+--------+