Sr Examen

Expresión BC∨(C⇔¬B)∨A

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    a∨(b∧c)∨(c⇔(¬b))
    $$a \vee \left(b \wedge c\right) \vee \left(c ⇔ \neg b\right)$$
    Solución detallada
    $$c ⇔ \neg b = \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$
    $$a \vee \left(b \wedge c\right) \vee \left(c ⇔ \neg b\right) = a \vee b \vee c$$
    Simplificación [src]
    $$a \vee b \vee c$$
    a∨b∨c
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    $$a \vee b \vee c$$
    a∨b∨c
    FNDP [src]
    $$a \vee b \vee c$$
    a∨b∨c
    FND [src]
    Ya está reducido a FND
    $$a \vee b \vee c$$
    a∨b∨c
    FNC [src]
    Ya está reducido a FNC
    $$a \vee b \vee c$$
    a∨b∨c