Sr Examen
Expresión cd+notc*notd
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(c∧d)∨((¬c)∧(¬d))
$$\left(c \wedge d\right) \vee \left(\neg c \wedge \neg d\right)$$
Simplificación
[src]
$$\left(c \wedge d\right) \vee \left(\neg c \wedge \neg d\right)$$
(c∧d)∨((¬c)∧(¬d))
Tabla de verdad
+---+---+--------+ | c | d | result | +===+===+========+ | 0 | 0 | 1 | +---+---+--------+ | 0 | 1 | 0 | +---+---+--------+ | 1 | 0 | 0 | +---+---+--------+ | 1 | 1 | 1 | +---+---+--------+
FND
[src]
Ya está reducido a FND
$$\left(c \wedge d\right) \vee \left(\neg c \wedge \neg d\right)$$
(c∧d)∨((¬c)∧(¬d))
FNC
[src]
$$\left(c \vee \neg c\right) \wedge \left(c \vee \neg d\right) \wedge \left(d \vee \neg c\right) \wedge \left(d \vee \neg d\right)$$
(c∨(¬c))∧(c∨(¬d))∧(d∨(¬c))∧(d∨(¬d))