Sr Examen

Expresión cd+notc*notd

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (c∧d)∨((¬c)∧(¬d))
    $$\left(c \wedge d\right) \vee \left(\neg c \wedge \neg d\right)$$
    Simplificación [src]
    $$\left(c \wedge d\right) \vee \left(\neg c \wedge \neg d\right)$$
    (c∧d)∨((¬c)∧(¬d))
    Tabla de verdad
    +---+---+--------+
    | c | d | result |
    +===+===+========+
    | 0 | 0 | 1      |
    +---+---+--------+
    | 0 | 1 | 0      |
    +---+---+--------+
    | 1 | 0 | 0      |
    +---+---+--------+
    | 1 | 1 | 1      |
    +---+---+--------+
    FNCD [src]
    $$\left(c \vee \neg d\right) \wedge \left(d \vee \neg c\right)$$
    (c∨(¬d))∧(d∨(¬c))
    FND [src]
    Ya está reducido a FND
    $$\left(c \wedge d\right) \vee \left(\neg c \wedge \neg d\right)$$
    (c∧d)∨((¬c)∧(¬d))
    FNDP [src]
    $$\left(c \wedge d\right) \vee \left(\neg c \wedge \neg d\right)$$
    (c∧d)∨((¬c)∧(¬d))
    FNC [src]
    $$\left(c \vee \neg c\right) \wedge \left(c \vee \neg d\right) \wedge \left(d \vee \neg c\right) \wedge \left(d \vee \neg d\right)$$
    (c∨(¬c))∧(c∨(¬d))∧(d∨(¬c))∧(d∨(¬d))