Expresión BD+BA+AC̅+BC
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg \left(\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(b \wedge d\right)\right) = \left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg d\right) \vee \left(\neg b \wedge \neg c\right)$$
$$\left(b \wedge c\right) \vee \neg \left(\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(b \wedge d\right)\right) = \left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg d\right) \vee \left(\neg b \wedge \neg c\right)$$
$$\left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg d\right) \vee \left(\neg b \wedge \neg c\right)$$
(b∧c)∨((¬a)∧(¬b))∨((¬a)∧(¬d))∨((¬b)∧(¬c))
Tabla de verdad
+---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
$$\left(b \vee \neg a \vee \neg b\right) \wedge \left(b \vee \neg a \vee \neg c\right) \wedge \left(b \vee \neg b \vee \neg d\right) \wedge \left(c \vee \neg a \vee \neg b\right) \wedge \left(c \vee \neg a \vee \neg c\right) \wedge \left(c \vee \neg b \vee \neg d\right) \wedge \left(b \vee \neg a \vee \neg b \vee \neg c\right) \wedge \left(b \vee \neg a \vee \neg b \vee \neg d\right) \wedge \left(b \vee \neg a \vee \neg c \vee \neg d\right) \wedge \left(b \vee \neg b \vee \neg c \vee \neg d\right) \wedge \left(c \vee \neg a \vee \neg b \vee \neg c\right) \wedge \left(c \vee \neg a \vee \neg b \vee \neg d\right) \wedge \left(c \vee \neg a \vee \neg c \vee \neg d\right) \wedge \left(c \vee \neg b \vee \neg c \vee \neg d\right)$$
(b∨(¬a)∨(¬b))∧(b∨(¬a)∨(¬c))∧(b∨(¬b)∨(¬d))∧(c∨(¬a)∨(¬b))∧(c∨(¬a)∨(¬c))∧(c∨(¬b)∨(¬d))∧(b∨(¬a)∨(¬b)∨(¬c))∧(b∨(¬a)∨(¬b)∨(¬d))∧(b∨(¬a)∨(¬c)∨(¬d))∧(b∨(¬b)∨(¬c)∨(¬d))∧(c∨(¬a)∨(¬b)∨(¬c))∧(c∨(¬a)∨(¬b)∨(¬d))∧(c∨(¬a)∨(¬c)∨(¬d))∧(c∨(¬b)∨(¬c)∨(¬d))
Ya está reducido a FND
$$\left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg d\right) \vee \left(\neg b \wedge \neg c\right)$$
(b∧c)∨((¬a)∧(¬b))∨((¬a)∧(¬d))∨((¬b)∧(¬c))
$$\left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg d\right) \vee \left(\neg b \wedge \neg c\right)$$
(b∧c)∨((¬a)∧(¬b))∨((¬a)∧(¬d))∨((¬b)∧(¬c))
$$\left(b \vee \neg a \vee \neg c\right) \wedge \left(c \vee \neg a \vee \neg b\right) \wedge \left(c \vee \neg b \vee \neg d\right)$$
(b∨(¬a)∨(¬c))∧(c∨(¬a)∨(¬b))∧(c∨(¬b)∨(¬d))