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Lógica matemática/ yvzv!z&(xv!z)

Expresión yvzv!z&(xv!z)

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    Solución

    Ha introducido [src] 
    y∨z∨((¬z)∧(x∨(¬z)))
    y∨z∨(¬z∧(x∨¬z))y \vee z \vee \left(\neg z \wedge \left(x \vee \neg z\right)\right)
    Solución detallada
    ¬z∧(x∨¬z)=¬z\neg z \wedge \left(x \vee \neg z\right) = \neg z
    y∨z∨(¬z∧(x∨¬z))=1y \vee z \vee \left(\neg z \wedge \left(x \vee \neg z\right)\right) = 1
    Simplificación [src]
    1 
    1
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    1 
    1
    FNDP [src]
    1 
    1
    FNCD [src]
    1 
    1
    FND [src]
    Ya está reducido a FND
    1 
    1
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