Sr Examen
Expresión yvzv!z&(xv!z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
y∨z∨((¬z)∧(x∨(¬z)))
$$y \vee z \vee \left(\neg z \wedge \left(x \vee \neg z\right)\right)$$
Solución detallada
$$\neg z \wedge \left(x \vee \neg z\right) = \neg z$$
$$y \vee z \vee \left(\neg z \wedge \left(x \vee \neg z\right)\right) = 1$$
$$y \vee z \vee \left(\neg z \wedge \left(x \vee \neg z\right)\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+