Expresión xyz∨x¬z
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(x∧¬z)∨(x∧y∧z)=x∧(y∨¬z)
x∧(y∨¬z)
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FNC
x∧(y∨¬z)
(x∧y)∨(x∧¬z)
(x∧y)∨(x∧¬z)
x∧(y∨¬z)