Expresión xyz∨x¬y¬z∨x¬z∨¬yz
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(x∧¬z)∨(z∧¬y)∨(x∧y∧z)∨(x∧¬y∧¬z)=x∨(z∧¬y)
x∨(z∧¬y)
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(x∨z)∧(x∨¬y)
Ya está reducido a FND
x∨(z∧¬y)
(x∨z)∧(x∨¬y)
x∨(z∧¬y)