Sr Examen

Expresión yz+x¬y

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (y∧z)∨(x∧(¬y))
    $$\left(x \wedge \neg y\right) \vee \left(y \wedge z\right)$$
    Simplificación [src]
    $$\left(x \wedge \neg y\right) \vee \left(y \wedge z\right)$$
    (y∧z)∨(x∧(¬y))
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    $$\left(x \wedge \neg y\right) \vee \left(y \wedge z\right)$$
    (y∧z)∨(x∧(¬y))
    FNC [src]
    $$\left(x \vee y\right) \wedge \left(x \vee z\right) \wedge \left(y \vee \neg y\right) \wedge \left(z \vee \neg y\right)$$
    (x∨y)∧(x∨z)∧(y∨(¬y))∧(z∨(¬y))
    FNCD [src]
    $$\left(x \vee y\right) \wedge \left(z \vee \neg y\right)$$
    (x∨y)∧(z∨(¬y))
    FND [src]
    Ya está reducido a FND
    $$\left(x \wedge \neg y\right) \vee \left(y \wedge z\right)$$
    (y∧z)∨(x∧(¬y))