Expresión yz+x¬y
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
(x∧¬y)∨(y∧z)
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(x∧¬y)∨(y∧z)
(x∨y)∧(x∨z)∧(y∨¬y)∧(z∨¬y)
(x∨y)∧(x∨z)∧(y∨(¬y))∧(z∨(¬y))
(x∨y)∧(z∨¬y)
Ya está reducido a FND
(x∧¬y)∨(y∧z)