Sr Examen
Lógica matemática/ yz+x¬y

Expresión yz+x¬y

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    (y∧z)∨(x∧(¬y))
    $$\left(x \wedge \neg y\right) \vee \left(y \wedge z\right)$$
    Simplificación [src]
    $$\left(x \wedge \neg y\right) \vee \left(y \wedge z\right)$$ 
    (y∧z)∨(x∧(¬y))
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNDP [src]
    $$\left(x \wedge \neg y\right) \vee \left(y \wedge z\right)$$ 
    (y∧z)∨(x∧(¬y))
    FNC [src]
    $$\left(x \vee y\right) \wedge \left(x \vee z\right) \wedge \left(y \vee \neg y\right) \wedge \left(z \vee \neg y\right)$$ 
    (x∨y)∧(x∨z)∧(y∨(¬y))∧(z∨(¬y))
    FNCD [src]
    $$\left(x \vee y\right) \wedge \left(z \vee \neg y\right)$$ 
    (x∨y)∧(z∨(¬y))
    FND [src]
    Ya está reducido a FND
    $$\left(x \wedge \neg y\right) \vee \left(y \wedge z\right)$$ 
    (y∧z)∨(x∧(¬y))
    © Sr Examen – Калькулятор