Sr Examen

Expresión avbvba&b&(b&cvc)va&c(a&b)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    a∨b∨(a∧b∧c)∨(a∧b∧(c∨(b∧c)))
    ab(abc)(ab(c(bc)))a \vee b \vee \left(a \wedge b \wedge c\right) \vee \left(a \wedge b \wedge \left(c \vee \left(b \wedge c\right)\right)\right)
    Solución detallada
    c(bc)=cc \vee \left(b \wedge c\right) = c
    ab(c(bc))=abca \wedge b \wedge \left(c \vee \left(b \wedge c\right)\right) = a \wedge b \wedge c
    ab(abc)(ab(c(bc)))=aba \vee b \vee \left(a \wedge b \wedge c\right) \vee \left(a \wedge b \wedge \left(c \vee \left(b \wedge c\right)\right)\right) = a \vee b
    Simplificación [src]
    aba \vee b
    a∨b
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    aba \vee b
    a∨b
    FNC [src]
    Ya está reducido a FNC
    aba \vee b
    a∨b
    FNDP [src]
    aba \vee b
    a∨b
    FNCD [src]
    aba \vee b
    a∨b