Sr Examen
Expresión cva&b+¬a&b&c
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
c∨(a∧b)∨(b∧c∧(¬a))
$$c \vee \left(a \wedge b\right) \vee \left(b \wedge c \wedge \neg a\right)$$
Solución detallada
$$c \vee \left(a \wedge b\right) \vee \left(b \wedge c \wedge \neg a\right) = c \vee \left(a \wedge b\right)$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+