Sr Examen

Expresión ¬P∨(¬Q∨R)∧(Q∨¬R)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬p)∨((q∨(¬r))∧(r∨(¬q)))
    ((q¬r)(r¬q))¬p\left(\left(q \vee \neg r\right) \wedge \left(r \vee \neg q\right)\right) \vee \neg p
    Solución detallada
    (q¬r)(r¬q)=(qr)(¬q¬r)\left(q \vee \neg r\right) \wedge \left(r \vee \neg q\right) = \left(q \wedge r\right) \vee \left(\neg q \wedge \neg r\right)
    ((q¬r)(r¬q))¬p=(qr)(¬q¬r)¬p\left(\left(q \vee \neg r\right) \wedge \left(r \vee \neg q\right)\right) \vee \neg p = \left(q \wedge r\right) \vee \left(\neg q \wedge \neg r\right) \vee \neg p
    Simplificación [src]
    (qr)(¬q¬r)¬p\left(q \wedge r\right) \vee \left(\neg q \wedge \neg r\right) \vee \neg p
    (¬p)∨(q∧r)∨((¬q)∧(¬r))
    Tabla de verdad
    +---+---+---+--------+
    | p | q | r | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    (qr)(¬q¬r)¬p\left(q \wedge r\right) \vee \left(\neg q \wedge \neg r\right) \vee \neg p
    (¬p)∨(q∧r)∨((¬q)∧(¬r))
    FNCD [src]
    (q¬p¬r)(r¬p¬q)\left(q \vee \neg p \vee \neg r\right) \wedge \left(r \vee \neg p \vee \neg q\right)
    (q∨(¬p)∨(¬r))∧(r∨(¬p)∨(¬q))
    FNC [src]
    (q¬p¬q)(q¬p¬r)(r¬p¬q)(r¬p¬r)\left(q \vee \neg p \vee \neg q\right) \wedge \left(q \vee \neg p \vee \neg r\right) \wedge \left(r \vee \neg p \vee \neg q\right) \wedge \left(r \vee \neg p \vee \neg r\right)
    (q∨(¬p)∨(¬q))∧(q∨(¬p)∨(¬r))∧(r∨(¬p)∨(¬q))∧(r∨(¬p)∨(¬r))
    FND [src]
    Ya está reducido a FND
    (qr)(¬q¬r)¬p\left(q \wedge r\right) \vee \left(\neg q \wedge \neg r\right) \vee \neg p
    (¬p)∨(q∧r)∨((¬q)∧(¬r))