Sr Examen
Expresión ¬a^b(bvc)va^¬b
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(a∧(¬b))∨(b∧(¬a)∧(b∨c))
$$\left(a \wedge \neg b\right) \vee \left(b \wedge \neg a \wedge \left(b \vee c\right)\right)$$
Solución detallada
$$b \wedge \neg a \wedge \left(b \vee c\right) = b \wedge \neg a$$
$$\left(a \wedge \neg b\right) \vee \left(b \wedge \neg a \wedge \left(b \vee c\right)\right) = \left(a \wedge \neg b\right) \vee \left(b \wedge \neg a\right)$$
$$\left(a \wedge \neg b\right) \vee \left(b \wedge \neg a \wedge \left(b \vee c\right)\right) = \left(a \wedge \neg b\right) \vee \left(b \wedge \neg a\right)$$
Simplificación
[src]
$$\left(a \wedge \neg b\right) \vee \left(b \wedge \neg a\right)$$
(a∧(¬b))∨(b∧(¬a))
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+
FNC
[src]
$$\left(a \vee b\right) \wedge \left(a \vee \neg a\right) \wedge \left(b \vee \neg b\right) \wedge \left(\neg a \vee \neg b\right)$$
(a∨b)∧(a∨(¬a))∧(b∨(¬b))∧((¬a)∨(¬b))
FND
[src]
Ya está reducido a FND
$$\left(a \wedge \neg b\right) \vee \left(b \wedge \neg a\right)$$
(a∧(¬b))∨(b∧(¬a))