Sr Examen
Expresión A⇒(B∧(C∨D))∧¬A⇒(C∨D)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(a⇒(b∧(¬a)∧(c∨d)))⇒(c∨d)
$$\left(a \Rightarrow \left(b \wedge \neg a \wedge \left(c \vee d\right)\right)\right) \Rightarrow \left(c \vee d\right)$$
Solución detallada
$$a \Rightarrow \left(b \wedge \neg a \wedge \left(c \vee d\right)\right) = \neg a$$
$$\left(a \Rightarrow \left(b \wedge \neg a \wedge \left(c \vee d\right)\right)\right) \Rightarrow \left(c \vee d\right) = a \vee c \vee d$$
$$\left(a \Rightarrow \left(b \wedge \neg a \wedge \left(c \vee d\right)\right)\right) \Rightarrow \left(c \vee d\right) = a \vee c \vee d$$
Tabla de verdad
+---+---+---+---+--------+ | a | b | c | d | result | +===+===+===+===+========+ | 0 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 0 | 1 | 1 | +---+---+---+---+--------+ | 0 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 0 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 0 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 1 | 1 | +---+---+---+---+--------+ | 0 | 1 | 1 | 0 | 1 | +---+---+---+---+--------+ | 0 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 0 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+