Sr Examen
Expresión z->(not(y->x))
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Solución
Solución detallada
$$y \Rightarrow x = x \vee \neg y$$
$$y \not\Rightarrow x = y \wedge \neg x$$
$$z \Rightarrow y \not\Rightarrow x = \left(y \wedge \neg x\right) \vee \neg z$$
$$y \not\Rightarrow x = y \wedge \neg x$$
$$z \Rightarrow y \not\Rightarrow x = \left(y \wedge \neg x\right) \vee \neg z$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+
FNCD
[src]
$$\left(y \vee \neg z\right) \wedge \left(\neg x \vee \neg z\right)$$
(y∨(¬z))∧((¬x)∨(¬z))
FNC
[src]
$$\left(y \vee \neg z\right) \wedge \left(\neg x \vee \neg z\right)$$
(y∨(¬z))∧((¬x)∨(¬z))