Expresión not(m1¬(m2)vm3¬(m1))vnot((not(m1¬(m2))vm3))&m1
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg \left(m_{1} \wedge \neg m_{2}\right) = m_{2} \vee \neg m_{1}$$
$$m_{3} \vee \neg \left(m_{1} \wedge \neg m_{2}\right) = m_{2} \vee m_{3} \vee \neg m_{1}$$
$$\neg \left(m_{3} \vee \neg \left(m_{1} \wedge \neg m_{2}\right)\right) = m_{1} \wedge \neg m_{2} \wedge \neg m_{3}$$
$$m_{1} \wedge \neg \left(m_{3} \vee \neg \left(m_{1} \wedge \neg m_{2}\right)\right) = m_{1} \wedge \neg m_{2} \wedge \neg m_{3}$$
$$\neg \left(\left(m_{1} \wedge \neg m_{2}\right) \vee \left(m_{3} \wedge \neg m_{1}\right)\right) = \left(m_{1} \wedge m_{2}\right) \vee \left(\neg m_{1} \wedge \neg m_{3}\right)$$
$$\left(m_{1} \wedge \neg \left(m_{3} \vee \neg \left(m_{1} \wedge \neg m_{2}\right)\right)\right) \vee \neg \left(\left(m_{1} \wedge \neg m_{2}\right) \vee \left(m_{3} \wedge \neg m_{1}\right)\right) = \left(m_{1} \wedge m_{2}\right) \vee \neg m_{3}$$
$$\left(m_{1} \wedge m_{2}\right) \vee \neg m_{3}$$
Tabla de verdad
+----+----+----+--------+
| m1 | m2 | m3 | result |
+====+====+====+========+
| 0 | 0 | 0 | 1 |
+----+----+----+--------+
| 0 | 0 | 1 | 0 |
+----+----+----+--------+
| 0 | 1 | 0 | 1 |
+----+----+----+--------+
| 0 | 1 | 1 | 0 |
+----+----+----+--------+
| 1 | 0 | 0 | 1 |
+----+----+----+--------+
| 1 | 0 | 1 | 0 |
+----+----+----+--------+
| 1 | 1 | 0 | 1 |
+----+----+----+--------+
| 1 | 1 | 1 | 1 |
+----+----+----+--------+
$$\left(m_{1} \wedge m_{2}\right) \vee \neg m_{3}$$
$$\left(m_{1} \vee \neg m_{3}\right) \wedge \left(m_{2} \vee \neg m_{3}\right)$$
$$\left(m_{1} \vee \neg m_{3}\right) \wedge \left(m_{2} \vee \neg m_{3}\right)$$
Ya está reducido a FND
$$\left(m_{1} \wedge m_{2}\right) \vee \neg m_{3}$$