Sr Examen
Expresión (a⇒(bvab¬c))∧¬b
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Solución
Ha introducido
[src]
(¬b)∧(a⇒(b∨(a∧b∧(¬c))))
$$\left(a \Rightarrow \left(b \vee \left(a \wedge b \wedge \neg c\right)\right)\right) \wedge \neg b$$
Solución detallada
$$b \vee \left(a \wedge b \wedge \neg c\right) = b$$
$$a \Rightarrow \left(b \vee \left(a \wedge b \wedge \neg c\right)\right) = b \vee \neg a$$
$$\left(a \Rightarrow \left(b \vee \left(a \wedge b \wedge \neg c\right)\right)\right) \wedge \neg b = \neg a \wedge \neg b$$
$$a \Rightarrow \left(b \vee \left(a \wedge b \wedge \neg c\right)\right) = b \vee \neg a$$
$$\left(a \Rightarrow \left(b \vee \left(a \wedge b \wedge \neg c\right)\right)\right) \wedge \neg b = \neg a \wedge \neg b$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+