Expresión (AandnotBandC)ornotAandB
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(b∧¬a)∨(a∧c∧¬b)=(a∨b)∧(b∨c)∧(¬a∨¬b)
(a∨b)∧(b∨c)∧(¬a∨¬b)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
(a∨b)∧(b∨c)∧(¬a∨¬b)
(b∧¬a)∨(a∧c∧¬b)
(b∧¬a)∨(b∧¬b)∨(a∧b∧¬a)∨(a∧b∧¬b)∨(a∧c∧¬a)∨(a∧c∧¬b)∨(b∧c∧¬a)∨(b∧c∧¬b)
(b∧(¬a))∨(b∧(¬b))∨(a∧b∧(¬a))∨(a∧b∧(¬b))∨(a∧c∧(¬a))∨(a∧c∧(¬b))∨(b∧c∧(¬a))∨(b∧c∧(¬b))
Ya está reducido a FNC
(a∨b)∧(b∨c)∧(¬a∨¬b)
