Sr Examen

Expresión not(not(borc)ora)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ¬(a∨(¬(b∨c)))
    ¬(a¬(bc))\neg \left(a \vee \neg \left(b \vee c\right)\right)
    Solución detallada
    ¬(bc)=¬b¬c\neg \left(b \vee c\right) = \neg b \wedge \neg c
    a¬(bc)=a(¬b¬c)a \vee \neg \left(b \vee c\right) = a \vee \left(\neg b \wedge \neg c\right)
    ¬(a¬(bc))=¬a(bc)\neg \left(a \vee \neg \left(b \vee c\right)\right) = \neg a \wedge \left(b \vee c\right)
    Simplificación [src]
    ¬a(bc)\neg a \wedge \left(b \vee c\right)
    (¬a)∧(b∨c)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FND [src]
    (b¬a)(c¬a)\left(b \wedge \neg a\right) \vee \left(c \wedge \neg a\right)
    (b∧(¬a))∨(c∧(¬a))
    FNDP [src]
    (b¬a)(c¬a)\left(b \wedge \neg a\right) \vee \left(c \wedge \neg a\right)
    (b∧(¬a))∨(c∧(¬a))
    FNCD [src]
    ¬a(bc)\neg a \wedge \left(b \vee c\right)
    (¬a)∧(b∨c)
    FNC [src]
    Ya está reducido a FNC
    ¬a(bc)\neg a \wedge \left(b \vee c\right)
    (¬a)∧(b∨c)