Expresión not(not(borc)ora)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
¬(b∨c)=¬b∧¬ca∨¬(b∨c)=a∨(¬b∧¬c)¬(a∨¬(b∨c))=¬a∧(b∨c)
¬a∧(b∨c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
(b∧¬a)∨(c∧¬a)
(b∧¬a)∨(c∧¬a)
¬a∧(b∨c)
Ya está reducido a FNC
¬a∧(b∨c)