Sr Examen

Expresión dandNOTaOR(bANDa)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧b)∨(d∧(¬a))
    $$\left(a \wedge b\right) \vee \left(d \wedge \neg a\right)$$
    Simplificación [src]
    $$\left(a \wedge b\right) \vee \left(d \wedge \neg a\right)$$
    (a∧b)∨(d∧(¬a))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | d | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$\left(a \wedge b\right) \vee \left(d \wedge \neg a\right)$$
    (a∧b)∨(d∧(¬a))
    FNCD [src]
    $$\left(a \vee d\right) \wedge \left(b \vee \neg a\right)$$
    (a∨d)∧(b∨(¬a))
    FNDP [src]
    $$\left(a \wedge b\right) \vee \left(d \wedge \neg a\right)$$
    (a∧b)∨(d∧(¬a))
    FNC [src]
    $$\left(a \vee d\right) \wedge \left(a \vee \neg a\right) \wedge \left(b \vee d\right) \wedge \left(b \vee \neg a\right)$$
    (a∨d)∧(b∨d)∧(a∨(¬a))∧(b∨(¬a))