Sr Examen
Lógica matemática/ (avbvc)&(avbvc)&(¬avbv¬c)

Expresión (avbvc)&(avbvc)&(¬avbv¬c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    (a∨b∨c)∧(b∨(¬a)∨(¬c))
    (a∨b∨c)∧(b∨¬a∨¬c)\left(a \vee b \vee c\right) \wedge \left(b \vee \neg a \vee \neg c\right)
    Solución detallada
    (a∨b∨c)∧(b∨¬a∨¬c)=b∨(a∧¬c)∨(c∧¬a)\left(a \vee b \vee c\right) \wedge \left(b \vee \neg a \vee \neg c\right) = b \vee \left(a \wedge \neg c\right) \vee \left(c \wedge \neg a\right)
    Simplificación [src]
    b∨(a∧¬c)∨(c∧¬a)b \vee \left(a \wedge \neg c\right) \vee \left(c \wedge \neg a\right) 
    b∨(a∧(¬c))∨(c∧(¬a))
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNC [src]
    (a∨b∨c)∧(a∨b∨¬a)∧(b∨c∨¬c)∧(b∨¬a∨¬c)\left(a \vee b \vee c\right) \wedge \left(a \vee b \vee \neg a\right) \wedge \left(b \vee c \vee \neg c\right) \wedge \left(b \vee \neg a \vee \neg c\right) 
    (a∨b∨c)∧(a∨b∨(¬a))∧(b∨c∨(¬c))∧(b∨(¬a)∨(¬c))
    FNCD [src]
    (a∨b∨c)∧(b∨¬a∨¬c)\left(a \vee b \vee c\right) \wedge \left(b \vee \neg a \vee \neg c\right) 
    (a∨b∨c)∧(b∨(¬a)∨(¬c))
    FNDP [src]
    b∨(a∧¬c)∨(c∧¬a)b \vee \left(a \wedge \neg c\right) \vee \left(c \wedge \neg a\right) 
    b∨(a∧(¬c))∨(c∧(¬a))
    FND [src]
    Ya está reducido a FND
    b∨(a∧¬c)∨(c∧¬a)b \vee \left(a \wedge \neg c\right) \vee \left(c \wedge \neg a\right) 
    b∨(a∧(¬c))∨(c∧(¬a))
    © Sr Examen – Калькулятор