Sr Examen

Expresión ¬y∧¬z∨x∧y∨p∧y∧z∨p∧x

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (p∧x)∨(x∧y)∨(p∧y∧z)∨((¬y)∧(¬z))
    $$\left(p \wedge x\right) \vee \left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right) \vee \left(p \wedge y \wedge z\right)$$
    Simplificación [src]
    $$\left(p \wedge x\right) \vee \left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right) \vee \left(p \wedge y \wedge z\right)$$
    (p∧x)∨(x∧y)∨(p∧y∧z)∨((¬y)∧(¬z))
    Tabla de verdad
    +---+---+---+---+--------+
    | p | x | y | z | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNDP [src]
    $$\left(p \wedge x\right) \vee \left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right) \vee \left(p \wedge y \wedge z\right)$$
    (p∧x)∨(x∧y)∨(p∧y∧z)∨((¬y)∧(¬z))
    FNCD [src]
    $$\left(p \vee x \vee \neg y\right) \wedge \left(p \vee y \vee \neg z\right) \wedge \left(x \vee y \vee \neg z\right) \wedge \left(x \vee z \vee \neg y\right)$$
    (p∨x∨(¬y))∧(p∨y∨(¬z))∧(x∨y∨(¬z))∧(x∨z∨(¬y))
    FND [src]
    Ya está reducido a FND
    $$\left(p \wedge x\right) \vee \left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right) \vee \left(p \wedge y \wedge z\right)$$
    (p∧x)∨(x∧y)∨(p∧y∧z)∨((¬y)∧(¬z))
    FNC [src]
    $$\left(p \vee x \vee \neg y\right) \wedge \left(p \vee x \vee \neg z\right) \wedge \left(p \vee y \vee \neg y\right) \wedge \left(p \vee y \vee \neg z\right) \wedge \left(x \vee y \vee \neg y\right) \wedge \left(x \vee y \vee \neg z\right) \wedge \left(x \vee z \vee \neg y\right) \wedge \left(x \vee z \vee \neg z\right) \wedge \left(p \vee x \vee y \vee \neg y\right) \wedge \left(p \vee x \vee y \vee \neg z\right) \wedge \left(p \vee x \vee z \vee \neg y\right) \wedge \left(p \vee x \vee z \vee \neg z\right) \wedge \left(p \vee y \vee z \vee \neg y\right) \wedge \left(p \vee y \vee z \vee \neg z\right) \wedge \left(x \vee y \vee z \vee \neg y\right) \wedge \left(x \vee y \vee z \vee \neg z\right)$$
    (p∨x∨(¬y))∧(p∨x∨(¬z))∧(p∨y∨(¬y))∧(p∨y∨(¬z))∧(x∨y∨(¬y))∧(x∨y∨(¬z))∧(x∨z∨(¬y))∧(x∨z∨(¬z))∧(p∨x∨y∨(¬y))∧(p∨x∨y∨(¬z))∧(p∨x∨z∨(¬y))∧(p∨x∨z∨(¬z))∧(p∨y∨z∨(¬y))∧(p∨y∨z∨(¬z))∧(x∨y∨z∨(¬y))∧(x∨y∨z∨(¬z))