Sr Examen
Expresión (avb)⊕(c⇒(¬a))
El profesor se sorprenderá mucho al ver tu solución correcta😉
⌨
Solución
Solución detallada
$$c \Rightarrow \neg a = \neg a \vee \neg c$$
$$\left(a \vee b\right) ⊕ \left(c \Rightarrow \neg a\right) = \left(a \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$
$$\left(a \vee b\right) ⊕ \left(c \Rightarrow \neg a\right) = \left(a \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$
Simplificación
[src]
$$\left(a \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$
(a∧c)∨((¬a)∧(¬b))
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+
FND
[src]
Ya está reducido a FND
$$\left(a \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$
(a∧c)∨((¬a)∧(¬b))
FNC
[src]
$$\left(a \vee \neg a\right) \wedge \left(a \vee \neg b\right) \wedge \left(c \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
(a∨(¬a))∧(a∨(¬b))∧(c∨(¬a))∧(c∨(¬b))