Sr Examen

Expresión ¬(((¬x)∨(¬y))∧((¬x)∨(¬z))∧((¬y)∨(¬z)))

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ¬(((¬x)∨(¬y))∧((¬x)∨(¬z))∧((¬y)∨(¬z)))
    ¬((¬x¬y)(¬x¬z)(¬y¬z))\neg \left(\left(\neg x \vee \neg y\right) \wedge \left(\neg x \vee \neg z\right) \wedge \left(\neg y \vee \neg z\right)\right)
    Solución detallada
    (¬x¬y)(¬x¬z)(¬y¬z)=(¬x¬y)(¬x¬z)(¬y¬z)\left(\neg x \vee \neg y\right) \wedge \left(\neg x \vee \neg z\right) \wedge \left(\neg y \vee \neg z\right) = \left(\neg x \wedge \neg y\right) \vee \left(\neg x \wedge \neg z\right) \vee \left(\neg y \wedge \neg z\right)
    ¬((¬x¬y)(¬x¬z)(¬y¬z))=(xy)(xz)(yz)\neg \left(\left(\neg x \vee \neg y\right) \wedge \left(\neg x \vee \neg z\right) \wedge \left(\neg y \vee \neg z\right)\right) = \left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(y \wedge z\right)
    Simplificación [src]
    (xy)(xz)(yz)\left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(y \wedge z\right)
    (x∧y)∨(x∧z)∨(y∧z)
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    (xy)(xz)(yz)\left(x \vee y\right) \wedge \left(x \vee z\right) \wedge \left(y \vee z\right)
    (x∨y)∧(x∨z)∧(y∨z)
    FNC [src]
    (xy)(xz)(yz)(xyz)\left(x \vee y\right) \wedge \left(x \vee z\right) \wedge \left(y \vee z\right) \wedge \left(x \vee y \vee z\right)
    (x∨y)∧(x∨z)∧(y∨z)∧(x∨y∨z)
    FNDP [src]
    (xy)(xz)(yz)\left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(y \wedge z\right)
    (x∧y)∨(x∧z)∨(y∧z)
    FND [src]
    Ya está reducido a FND
    (xy)(xz)(yz)\left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(y \wedge z\right)
    (x∧y)∨(x∧z)∨(y∧z)