Sr Examen

Expresión (¬zyv¬yz)xvyz

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (y∧z)∨(x∧((y∧(¬z))∨(z∧(¬y))))
    $$\left(x \wedge \left(\left(y \wedge \neg z\right) \vee \left(z \wedge \neg y\right)\right)\right) \vee \left(y \wedge z\right)$$
    Solución detallada
    $$x \wedge \left(\left(y \wedge \neg z\right) \vee \left(z \wedge \neg y\right)\right) = x \wedge \left(y \vee z\right) \wedge \left(\neg y \vee \neg z\right)$$
    $$\left(x \wedge \left(\left(y \wedge \neg z\right) \vee \left(z \wedge \neg y\right)\right)\right) \vee \left(y \wedge z\right) = \left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(y \wedge z\right)$$
    Simplificación [src]
    $$\left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(y \wedge z\right)$$
    (x∧y)∨(x∧z)∨(y∧z)
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    $$\left(x \vee y\right) \wedge \left(x \vee z\right) \wedge \left(y \vee z\right) \wedge \left(x \vee y \vee z\right)$$
    (x∨y)∧(x∨z)∧(y∨z)∧(x∨y∨z)
    FND [src]
    Ya está reducido a FND
    $$\left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(y \wedge z\right)$$
    (x∧y)∨(x∧z)∨(y∧z)
    FNCD [src]
    $$\left(x \vee y\right) \wedge \left(x \vee z\right) \wedge \left(y \vee z\right)$$
    (x∨y)∧(x∨z)∧(y∨z)
    FNDP [src]
    $$\left(x \wedge y\right) \vee \left(x \wedge z\right) \vee \left(y \wedge z\right)$$
    (x∧y)∨(x∧z)∨(y∧z)