Expresión (a&c)v(b&d)(avb)&(c&d)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
b∧c∧d∧(a∨b)=b∧c∧d(a∧c)∨(b∧c∧d∧(a∨b))=c∧(a∨b)∧(a∨d)
c∧(a∨b)∧(a∨d)
Tabla de verdad
+---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
(a∧c)∨(a∧b∧c)∨(a∧c∧d)∨(b∧c∧d)
(a∧c)∨(a∧b∧c)∨(a∧c∧d)∨(b∧c∧d)
c∧(a∨b)∧(a∨d)
Ya está reducido a FNC
c∧(a∨b)∧(a∨d)
(a∧c)∨(b∧c∧d)