Sr Examen
Expresión (a&c)v(b&d)(avb)&(c&d)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(a∧c)∨(b∧c∧d∧(a∨b))
$$\left(a \wedge c\right) \vee \left(b \wedge c \wedge d \wedge \left(a \vee b\right)\right)$$
Solución detallada
$$b \wedge c \wedge d \wedge \left(a \vee b\right) = b \wedge c \wedge d$$
$$\left(a \wedge c\right) \vee \left(b \wedge c \wedge d \wedge \left(a \vee b\right)\right) = c \wedge \left(a \vee b\right) \wedge \left(a \vee d\right)$$
$$\left(a \wedge c\right) \vee \left(b \wedge c \wedge d \wedge \left(a \vee b\right)\right) = c \wedge \left(a \vee b\right) \wedge \left(a \vee d\right)$$
Tabla de verdad
+---+---+---+---+--------+ | a | b | c | d | result | +===+===+===+===+========+ | 0 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 0 | 1 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 1 | 1 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 1 | 0 | 0 | 1 | 0 | +---+---+---+---+--------+ | 1 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 1 | 1 | 0 | 1 | 0 | +---+---+---+---+--------+ | 1 | 1 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+
FND
[src]
$$\left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right) \vee \left(a \wedge c \wedge d\right) \vee \left(b \wedge c \wedge d\right)$$
(a∧c)∨(a∧b∧c)∨(a∧c∧d)∨(b∧c∧d)
FNC
[src]
Ya está reducido a FNC
$$c \wedge \left(a \vee b\right) \wedge \left(a \vee d\right)$$
c∧(a∨b)∧(a∨d)