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Lógica matemática/ {(\neg{A}\lor{A})\land(1\lor0)\lor(0\land1)}(¬A∨A)∧(1∨0)∨(0∧1)

Expresión {(\neg{A}\lor{A})\land(1\lor0)\lor(0\land1)}(¬A∨A)∧(1∨0)∨(0∧1)

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (a∨(¬a))∧(((a∧e∧g∧n)|(a∨l))|(l∧(1|l))|(l∨(0|l)))
    (((a∧e∧g∧n)∣(a∨l))∣(l∧(1∣l))∣(l∨(0∣l)))∧(a∨¬a)\left(\left(\left(a \wedge e \wedge g \wedge n\right) | \left(a \vee l\right)\right) | \left(l \wedge \left(1 | l\right)\right) | \left(l \vee \left(0 | l\right)\right)\right) \wedge \left(a \vee \neg a\right)
    Solución detallada
    a∨¬a=1a \vee \neg a = 1
    (a∧e∧g∧n)∣(a∨l)=¬a∨¬e∨¬g∨¬n\left(a \wedge e \wedge g \wedge n\right) | \left(a \vee l\right) = \neg a \vee \neg e \vee \neg g \vee \neg n
    1∣l=¬l1 | l = \neg l
    l∧(1∣l)=Falsel \wedge \left(1 | l\right) = \text{False}
    0∣l=10 | l = 1
    l∨(0∣l)=1l \vee \left(0 | l\right) = 1
    ((a∧e∧g∧n)∣(a∨l))∣(l∧(1∣l))∣(l∨(0∣l))=1\left(\left(a \wedge e \wedge g \wedge n\right) | \left(a \vee l\right)\right) | \left(l \wedge \left(1 | l\right)\right) | \left(l \vee \left(0 | l\right)\right) = 1
    (((a∧e∧g∧n)∣(a∨l))∣(l∧(1∣l))∣(l∨(0∣l)))∧(a∨¬a)=1\left(\left(\left(a \wedge e \wedge g \wedge n\right) | \left(a \vee l\right)\right) | \left(l \wedge \left(1 | l\right)\right) | \left(l \vee \left(0 | l\right)\right)\right) \wedge \left(a \vee \neg a\right) = 1
    Simplificación [src]
    1 
    1
    Tabla de verdad 
    +---+---+---+---+---+--------+
| a | e | g | l | n | result |
+===+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0 | 1      |
+---+---+---+---+---+--------+
| 0 | 0 | 0 | 0 | 1 | 1      |
+---+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0 | 1      |
+---+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1 | 1      |
+---+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0 | 1      |
+---+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0 | 1      |
+---+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1 | 1      |
+---+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0 | 1      |
+---+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 0 | 1      |
+---+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0 | 1      |
+---+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 1 | 1      |
+---+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0 | 1      |
+---+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1 | 1      |
+---+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0 | 1      |
+---+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0 | 1      |
+---+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 1 | 1      |
+---+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0 | 1      |
+---+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 0 | 1      |
+---+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+---+--------+
    FNDP [src]
    1 
    1
    FND [src]
    Ya está reducido a FND
    1 
    1
    FNCD [src]
    1 
    1
    FNC [src]
    Ya está reducido a FNC
    1 
    1
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