Sr Examen
Expresión —(А&В)^(—(А&В)→(А&В))
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(¬(a∧b))∧((¬(a∧b))⇒(a∧b))
$$\left(\neg \left(a \wedge b\right) \Rightarrow \left(a \wedge b\right)\right) \wedge \neg \left(a \wedge b\right)$$
Solución detallada
$$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
$$\neg \left(a \wedge b\right) \Rightarrow \left(a \wedge b\right) = a \wedge b$$
$$\left(\neg \left(a \wedge b\right) \Rightarrow \left(a \wedge b\right)\right) \wedge \neg \left(a \wedge b\right) = \text{False}$$
$$\neg \left(a \wedge b\right) \Rightarrow \left(a \wedge b\right) = a \wedge b$$
$$\left(\neg \left(a \wedge b\right) \Rightarrow \left(a \wedge b\right)\right) \wedge \neg \left(a \wedge b\right) = \text{False}$$
Tabla de verdad
+---+---+--------+ | a | b | result | +===+===+========+ | 0 | 0 | 0 | +---+---+--------+ | 0 | 1 | 0 | +---+---+--------+ | 1 | 0 | 0 | +---+---+--------+ | 1 | 1 | 0 | +---+---+--------+