Sr Examen

ExpresiΓ³n βˆ’(π‘βˆ¨π‘ž)∨(βˆ’π‘βˆ§π‘ž)β†’(βˆ’π‘βˆ§π‘ž)

El profesor se sorprenderΓ‘ mucho al ver tu soluciΓ³n correctaπŸ˜‰

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    SoluciΓ³n

    Ha introducido [src]
    ((q∧(Β¬p))∨(Β¬(p∨q)))β‡’(q∧(Β¬p))
    $$\left(\left(q \wedge \neg p\right) \vee \neg \left(p \vee q\right)\right) \Rightarrow \left(q \wedge \neg p\right)$$
    SoluciΓ³n detallada
    $$\neg \left(p \vee q\right) = \neg p \wedge \neg q$$
    $$\left(q \wedge \neg p\right) \vee \neg \left(p \vee q\right) = \neg p$$
    $$\left(\left(q \wedge \neg p\right) \vee \neg \left(p \vee q\right)\right) \Rightarrow \left(q \wedge \neg p\right) = p \vee q$$
    SimplificaciΓ³n [src]
    $$p \vee q$$
    p∨q
    Tabla de verdad
    +---+---+--------+
    | p | q | result |
    +===+===+========+
    | 0 | 0 | 0      |
    +---+---+--------+
    | 0 | 1 | 1      |
    +---+---+--------+
    | 1 | 0 | 1      |
    +---+---+--------+
    | 1 | 1 | 1      |
    +---+---+--------+
    FND [src]
    Ya estΓ‘ reducido a FND
    $$p \vee q$$
    p∨q
    FNC [src]
    Ya estΓ‘ reducido a FNC
    $$p \vee q$$
    p∨q
    FNCD [src]
    $$p \vee q$$
    p∨q
    FNDP [src]
    $$p \vee q$$
    p∨q