Sr Examen
Expresión xzy⇒(¬x)∨(¬y)∨z
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(x∧y∧z)⇒(z∨(¬x)∨(¬y))
$$\left(x \wedge y \wedge z\right) \Rightarrow \left(z \vee \neg x \vee \neg y\right)$$
Solución detallada
$$\left(x \wedge y \wedge z\right) \Rightarrow \left(z \vee \neg x \vee \neg y\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+