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Expresión (¬avb)v(¬bvc)∧(a∧¬b)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    b∨(¬a)∨(a∧(¬b)∧(c∨(¬b)))
    b(a¬b(c¬b))¬ab \vee \left(a \wedge \neg b \wedge \left(c \vee \neg b\right)\right) \vee \neg a
    Solución detallada
    a¬b(c¬b)=a¬ba \wedge \neg b \wedge \left(c \vee \neg b\right) = a \wedge \neg b
    b(a¬b(c¬b))¬a=1b \vee \left(a \wedge \neg b \wedge \left(c \vee \neg b\right)\right) \vee \neg a = 1
    Simplificación [src]
    1
    1
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    1
    1
    FND [src]
    Ya está reducido a FND
    1
    1
    FNC [src]
    Ya está reducido a FNC
    1
    1
    FNDP [src]
    1
    1