Sr Examen

Expresión ¬((¬P∧Q)∨¬(R∨¬S))

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ¬((q∧(¬p))∨(¬(r∨(¬s))))
    $$\neg \left(\left(q \wedge \neg p\right) \vee \neg \left(r \vee \neg s\right)\right)$$
    Solución detallada
    $$\neg \left(r \vee \neg s\right) = s \wedge \neg r$$
    $$\left(q \wedge \neg p\right) \vee \neg \left(r \vee \neg s\right) = \left(q \vee s\right) \wedge \left(q \vee \neg r\right) \wedge \left(s \vee \neg p\right) \wedge \left(\neg p \vee \neg r\right)$$
    $$\neg \left(\left(q \wedge \neg p\right) \vee \neg \left(r \vee \neg s\right)\right) = \left(p \wedge r\right) \vee \left(p \wedge \neg s\right) \vee \left(r \wedge \neg q\right) \vee \left(\neg q \wedge \neg s\right)$$
    Simplificación [src]
    $$\left(p \wedge r\right) \vee \left(p \wedge \neg s\right) \vee \left(r \wedge \neg q\right) \vee \left(\neg q \wedge \neg s\right)$$
    (p∧r)∨(p∧(¬s))∨(r∧(¬q))∨((¬q)∧(¬s))
    Tabla de verdad
    +---+---+---+---+--------+
    | p | q | r | s | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNDP [src]
    $$\left(p \wedge r\right) \vee \left(p \wedge \neg s\right) \vee \left(r \wedge \neg q\right) \vee \left(\neg q \wedge \neg s\right)$$
    (p∧r)∨(p∧(¬s))∨(r∧(¬q))∨((¬q)∧(¬s))
    FND [src]
    Ya está reducido a FND
    $$\left(p \wedge r\right) \vee \left(p \wedge \neg s\right) \vee \left(r \wedge \neg q\right) \vee \left(\neg q \wedge \neg s\right)$$
    (p∧r)∨(p∧(¬s))∨(r∧(¬q))∨((¬q)∧(¬s))
    FNC [src]
    $$\left(p \vee \neg q\right) \wedge \left(r \vee \neg s\right) \wedge \left(p \vee r \vee \neg q\right) \wedge \left(p \vee r \vee \neg s\right) \wedge \left(p \vee \neg q \vee \neg s\right) \wedge \left(r \vee \neg q \vee \neg s\right) \wedge \left(p \vee r \vee \neg q \vee \neg s\right)$$
    (p∨(¬q))∧(r∨(¬s))∧(p∨r∨(¬q))∧(p∨r∨(¬s))∧(p∨(¬q)∨(¬s))∧(r∨(¬q)∨(¬s))∧(p∨r∨(¬q)∨(¬s))
    FNCD [src]
    $$\left(p \vee \neg q\right) \wedge \left(r \vee \neg s\right)$$
    (p∨(¬q))∧(r∨(¬s))