Expresión ¬(¬(a&b)v¬(cvb)&avc)v¬(bvc)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg \left(b \vee c\right) = \neg b \wedge \neg c$$
$$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
$$a \wedge \neg \left(b \vee c\right) = a \wedge \neg b \wedge \neg c$$
$$c \vee \left(a \wedge \neg \left(b \vee c\right)\right) \vee \neg \left(a \wedge b\right) = c \vee \neg a \vee \neg b$$
$$\neg \left(c \vee \left(a \wedge \neg \left(b \vee c\right)\right) \vee \neg \left(a \wedge b\right)\right) = a \wedge b \wedge \neg c$$
$$\neg \left(b \vee c\right) \vee \neg \left(c \vee \left(a \wedge \neg \left(b \vee c\right)\right) \vee \neg \left(a \wedge b\right)\right) = \neg c \wedge \left(a \vee \neg b\right)$$
$$\neg c \wedge \left(a \vee \neg b\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
$$\left(a \wedge \neg c\right) \vee \left(\neg b \wedge \neg c\right)$$
Ya está reducido a FNC
$$\neg c \wedge \left(a \vee \neg b\right)$$
$$\left(a \wedge \neg c\right) \vee \left(\neg b \wedge \neg c\right)$$
$$\neg c \wedge \left(a \vee \neg b\right)$$