Sr Examen

Expresión ¬(¬(a&b)v¬(cvb)&avc)v¬(bvc)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬(b∨c))∨(¬(c∨(¬(a∧b))∨(a∧(¬(b∨c)))))
    $$\neg \left(b \vee c\right) \vee \neg \left(c \vee \left(a \wedge \neg \left(b \vee c\right)\right) \vee \neg \left(a \wedge b\right)\right)$$
    Solución detallada
    $$\neg \left(b \vee c\right) = \neg b \wedge \neg c$$
    $$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
    $$a \wedge \neg \left(b \vee c\right) = a \wedge \neg b \wedge \neg c$$
    $$c \vee \left(a \wedge \neg \left(b \vee c\right)\right) \vee \neg \left(a \wedge b\right) = c \vee \neg a \vee \neg b$$
    $$\neg \left(c \vee \left(a \wedge \neg \left(b \vee c\right)\right) \vee \neg \left(a \wedge b\right)\right) = a \wedge b \wedge \neg c$$
    $$\neg \left(b \vee c\right) \vee \neg \left(c \vee \left(a \wedge \neg \left(b \vee c\right)\right) \vee \neg \left(a \wedge b\right)\right) = \neg c \wedge \left(a \vee \neg b\right)$$
    Simplificación [src]
    $$\neg c \wedge \left(a \vee \neg b\right)$$
    (¬c)∧(a∨(¬b))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FND [src]
    $$\left(a \wedge \neg c\right) \vee \left(\neg b \wedge \neg c\right)$$
    (a∧(¬c))∨((¬b)∧(¬c))
    FNC [src]
    Ya está reducido a FNC
    $$\neg c \wedge \left(a \vee \neg b\right)$$
    (¬c)∧(a∨(¬b))
    FNDP [src]
    $$\left(a \wedge \neg c\right) \vee \left(\neg b \wedge \neg c\right)$$
    (a∧(¬c))∨((¬b)∧(¬c))
    FNCD [src]
    $$\neg c \wedge \left(a \vee \neg b\right)$$
    (¬c)∧(a∨(¬b))