Expresión (x+(!y))*(y+(!z))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(x \vee \neg y\right) \wedge \left(y \vee \neg z\right) = \left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right)$$
$$\left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right)$$
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(x \vee \neg y\right) \wedge \left(x \vee \neg z\right) \wedge \left(y \vee \neg y\right) \wedge \left(y \vee \neg z\right)$$
(x∨(¬y))∧(x∨(¬z))∧(y∨(¬y))∧(y∨(¬z))
$$\left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right)$$
Ya está reducido a FND
$$\left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right)$$
$$\left(x \vee \neg y\right) \wedge \left(y \vee \neg z\right)$$