Sr Examen
Expresión (x+(!y))*(y+(!z))
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(x∨(¬y))∧(y∨(¬z))
$$\left(x \vee \neg y\right) \wedge \left(y \vee \neg z\right)$$
Solución detallada
$$\left(x \vee \neg y\right) \wedge \left(y \vee \neg z\right) = \left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right)$$
Simplificación
[src]
$$\left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right)$$
(x∧y)∨((¬y)∧(¬z))
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+
FNC
[src]
$$\left(x \vee \neg y\right) \wedge \left(x \vee \neg z\right) \wedge \left(y \vee \neg y\right) \wedge \left(y \vee \neg z\right)$$
(x∨(¬y))∧(x∨(¬z))∧(y∨(¬y))∧(y∨(¬z))
FND
[src]
Ya está reducido a FND
$$\left(x \wedge y\right) \vee \left(\neg y \wedge \neg z\right)$$
(x∧y)∨((¬y)∧(¬z))