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Expresión ¬a∨¬b∨¬c∨¬b∨(¬a∨¬¬b∨¬c∧¬¬a∨¬b∨¬c)∨¬a∧¬b
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(¬a)∨(¬b)∨(¬c)∨(¬(¬b))∨((¬a)∧(¬b))∨((¬c)∧(¬(¬a)))
$$\left(\neg a \wedge \neg b\right) \vee \left(\neg c \wedge \neg \left(\neg a\right)\right) \vee \neg a \vee \neg b \vee \neg c \vee \neg \left(\neg b\right)$$
Solución detallada
$$\neg \left(\neg b\right) = b$$
$$\neg \left(\neg a\right) = a$$
$$\neg c \wedge \neg \left(\neg a\right) = a \wedge \neg c$$
$$\left(\neg a \wedge \neg b\right) \vee \left(\neg c \wedge \neg \left(\neg a\right)\right) \vee \neg a \vee \neg b \vee \neg c \vee \neg \left(\neg b\right) = 1$$
$$\neg \left(\neg a\right) = a$$
$$\neg c \wedge \neg \left(\neg a\right) = a \wedge \neg c$$
$$\left(\neg a \wedge \neg b\right) \vee \left(\neg c \wedge \neg \left(\neg a\right)\right) \vee \neg a \vee \neg b \vee \neg c \vee \neg \left(\neg b\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+