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Lógica matemática/ ¬A∧B∨C∧D∨A∧D

Expresión ¬A∧B∨C∧D∨A∧D

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (a∧d)∨(c∧d)∨(b∧(¬a))
    $$\left(a \wedge d\right) \vee \left(b \wedge \neg a\right) \vee \left(c \wedge d\right)$$
    Simplificación [src]
    $$\left(a \wedge d\right) \vee \left(b \wedge \neg a\right) \vee \left(c \wedge d\right)$$ 
    (a∧d)∨(c∧d)∨(b∧(¬a))
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FNCD [src]
    $$\left(b \vee d\right) \wedge \left(d \vee \neg a\right) \wedge \left(a \vee b \vee c\right)$$ 
    (b∨d)∧(d∨(¬a))∧(a∨b∨c)
    FNC [src]
    $$\left(b \vee d\right) \wedge \left(d \vee \neg a\right) \wedge \left(a \vee b \vee c\right) \wedge \left(a \vee b \vee d\right) \wedge \left(a \vee c \vee \neg a\right) \wedge \left(a \vee d \vee \neg a\right) \wedge \left(b \vee c \vee d\right) \wedge \left(c \vee d \vee \neg a\right)$$ 
    (b∨d)∧(d∨(¬a))∧(a∨b∨c)∧(a∨b∨d)∧(b∨c∨d)∧(a∨c∨(¬a))∧(a∨d∨(¬a))∧(c∨d∨(¬a))
    FND [src]
    Ya está reducido a FND
    $$\left(a \wedge d\right) \vee \left(b \wedge \neg a\right) \vee \left(c \wedge d\right)$$ 
    (a∧d)∨(c∧d)∨(b∧(¬a))
    FNDP [src]
    $$\left(a \wedge d\right) \vee \left(b \wedge \neg a\right) \vee \left(c \wedge d\right)$$ 
    (a∧d)∨(c∧d)∨(b∧(¬a))
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