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Lógica matemática/ avb&¬(a&b&c)

Expresión avb&¬(a&b&c)

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    Solución

    Ha introducido [src] 
    a∨(b∧(¬(a∧b∧c)))
    a∨(b∧¬(a∧b∧c))a \vee \left(b \wedge \neg \left(a \wedge b \wedge c\right)\right)
    Solución detallada
    ¬(a∧b∧c)=¬a∨¬b∨¬c\neg \left(a \wedge b \wedge c\right) = \neg a \vee \neg b \vee \neg c
    b∧¬(a∧b∧c)=b∧(¬a∨¬c)b \wedge \neg \left(a \wedge b \wedge c\right) = b \wedge \left(\neg a \vee \neg c\right)
    a∨(b∧¬(a∧b∧c))=a∨ba \vee \left(b \wedge \neg \left(a \wedge b \wedge c\right)\right) = a \vee b
    Simplificación [src]
    a∨ba \vee b 
    a∨b
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    a∨ba \vee b 
    a∨b
    FNCD [src]
    a∨ba \vee b 
    a∨b
    FNC [src]
    Ya está reducido a FNC
    a∨ba \vee b 
    a∨b
    FNDP [src]
    a∨ba \vee b 
    a∨b
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