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Lógica matemática/ {{pv[s^(¬pvs)]}^(pvs)}^[p^(svr)]

Expresión {{pv[s^(¬pvs)]}^(pvs)}^[p^(svr)]

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    p∧(p∨s)∧(r∨s)∧(p∨(s∧(s∨(¬p))))
    $$p \wedge \left(p \vee s\right) \wedge \left(p \vee \left(s \wedge \left(s \vee \neg p\right)\right)\right) \wedge \left(r \vee s\right)$$
    Solución detallada
    $$s \wedge \left(s \vee \neg p\right) = s$$
    $$p \vee \left(s \wedge \left(s \vee \neg p\right)\right) = p \vee s$$
    $$p \wedge \left(p \vee s\right) \wedge \left(p \vee \left(s \wedge \left(s \vee \neg p\right)\right)\right) \wedge \left(r \vee s\right) = p \wedge \left(r \vee s\right)$$
    Simplificación [src]
    $$p \wedge \left(r \vee s\right)$$ 
    p∧(r∨s)
    Tabla de verdad 
    +---+---+---+--------+
| p | r | s | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNCD [src]
    $$p \wedge \left(r \vee s\right)$$ 
    p∧(r∨s)
    FNC [src]
    Ya está reducido a FNC
    $$p \wedge \left(r \vee s\right)$$ 
    p∧(r∨s)
    FND [src]
    $$\left(p \wedge r\right) \vee \left(p \wedge s\right)$$ 
    (p∧r)∨(p∧s)
    FNDP [src]
    $$\left(p \wedge r\right) \vee \left(p \wedge s\right)$$ 
    (p∧r)∨(p∧s)
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