Sr Examen
Lógica matemática/ DA+CA+BA

Expresión DA+CA+BA

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    (a∧b)∨(a∧c)∨(a∧d)
    $$\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(a \wedge d\right)$$
    Solución detallada
    $$\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(a \wedge d\right) = a \wedge \left(b \vee c \vee d\right)$$
    Simplificación [src]
    $$a \wedge \left(b \vee c \vee d\right)$$ 
    a∧(b∨c∨d)
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FND [src]
    $$\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(a \wedge d\right)$$ 
    (a∧b)∨(a∧c)∨(a∧d)
    FNC [src]
    Ya está reducido a FNC
    $$a \wedge \left(b \vee c \vee d\right)$$ 
    a∧(b∨c∨d)
    FNDP [src]
    $$\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(a \wedge d\right)$$ 
    (a∧b)∨(a∧c)∨(a∧d)
    FNCD [src]
    $$a \wedge \left(b \vee c \vee d\right)$$ 
    a∧(b∨c∨d)
    © Sr Examen – Калькулятор