Expresión not(not(aandnotb)oraandbandnotc)andnot((aorcorb)andnot(aandnotc))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg \left(a \wedge \neg c\right) = c \vee \neg a$$
$$\neg \left(a \wedge \neg c\right) \wedge \left(a \vee b \vee c\right) = c \vee \left(b \wedge \neg a\right)$$
$$\neg \left(\neg \left(a \wedge \neg c\right) \wedge \left(a \vee b \vee c\right)\right) = \neg c \wedge \left(a \vee \neg b\right)$$
$$\neg \left(a \wedge \neg b\right) = b \vee \neg a$$
$$\left(a \wedge b \wedge \neg c\right) \vee \neg \left(a \wedge \neg b\right) = b \vee \neg a$$
$$\neg \left(\left(a \wedge b \wedge \neg c\right) \vee \neg \left(a \wedge \neg b\right)\right) = a \wedge \neg b$$
$$\neg \left(\neg \left(a \wedge \neg c\right) \wedge \left(a \vee b \vee c\right)\right) \wedge \neg \left(\left(a \wedge b \wedge \neg c\right) \vee \neg \left(a \wedge \neg b\right)\right) = a \wedge \neg b \wedge \neg c$$
$$a \wedge \neg b \wedge \neg c$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
$$a \wedge \neg b \wedge \neg c$$
$$a \wedge \neg b \wedge \neg c$$
Ya está reducido a FND
$$a \wedge \neg b \wedge \neg c$$
Ya está reducido a FNC
$$a \wedge \neg b \wedge \neg c$$