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Expresión not(not(aandnotb)oraandbandnotc)andnot((aorcorb)andnot(aandnotc))

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬((a∨b∨c)∧(¬(a∧(¬c)))))∧(¬((a∧b∧(¬c))∨(¬(a∧(¬b)))))
    $$\neg \left(\neg \left(a \wedge \neg c\right) \wedge \left(a \vee b \vee c\right)\right) \wedge \neg \left(\left(a \wedge b \wedge \neg c\right) \vee \neg \left(a \wedge \neg b\right)\right)$$
    Solución detallada
    $$\neg \left(a \wedge \neg c\right) = c \vee \neg a$$
    $$\neg \left(a \wedge \neg c\right) \wedge \left(a \vee b \vee c\right) = c \vee \left(b \wedge \neg a\right)$$
    $$\neg \left(\neg \left(a \wedge \neg c\right) \wedge \left(a \vee b \vee c\right)\right) = \neg c \wedge \left(a \vee \neg b\right)$$
    $$\neg \left(a \wedge \neg b\right) = b \vee \neg a$$
    $$\left(a \wedge b \wedge \neg c\right) \vee \neg \left(a \wedge \neg b\right) = b \vee \neg a$$
    $$\neg \left(\left(a \wedge b \wedge \neg c\right) \vee \neg \left(a \wedge \neg b\right)\right) = a \wedge \neg b$$
    $$\neg \left(\neg \left(a \wedge \neg c\right) \wedge \left(a \vee b \vee c\right)\right) \wedge \neg \left(\left(a \wedge b \wedge \neg c\right) \vee \neg \left(a \wedge \neg b\right)\right) = a \wedge \neg b \wedge \neg c$$
    Simplificación [src]
    $$a \wedge \neg b \wedge \neg c$$
    a∧(¬b)∧(¬c)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNCD [src]
    $$a \wedge \neg b \wedge \neg c$$
    a∧(¬b)∧(¬c)
    FNDP [src]
    $$a \wedge \neg b \wedge \neg c$$
    a∧(¬b)∧(¬c)
    FND [src]
    Ya está reducido a FND
    $$a \wedge \neg b \wedge \neg c$$
    a∧(¬b)∧(¬c)
    FNC [src]
    Ya está reducido a FNC
    $$a \wedge \neg b \wedge \neg c$$
    a∧(¬b)∧(¬c)