Sr Examen

Expresión not(aor(not(b)andc))

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    Solución

    Ha introducido [src]
    ¬(a∨(c∧(¬b)))
    $$\neg \left(a \vee \left(c \wedge \neg b\right)\right)$$
    Solución detallada
    $$\neg \left(a \vee \left(c \wedge \neg b\right)\right) = \neg a \wedge \left(b \vee \neg c\right)$$
    Simplificación [src]
    $$\neg a \wedge \left(b \vee \neg c\right)$$
    (¬a)∧(b∨(¬c))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FND [src]
    $$\left(b \wedge \neg a\right) \vee \left(\neg a \wedge \neg c\right)$$
    (b∧(¬a))∨((¬a)∧(¬c))
    FNCD [src]
    $$\neg a \wedge \left(b \vee \neg c\right)$$
    (¬a)∧(b∨(¬c))
    FNC [src]
    Ya está reducido a FNC
    $$\neg a \wedge \left(b \vee \neg c\right)$$
    (¬a)∧(b∨(¬c))
    FNDP [src]
    $$\left(b \wedge \neg a\right) \vee \left(\neg a \wedge \neg c\right)$$
    (b∧(¬a))∨((¬a)∧(¬c))